Find the number of digits of a given number

        public static int NumberOfDigits(int n)
        {
            int counter = 0;
            while (n > 0)
            {
                n = n / 10;
                counter++;
            }
            return counter;
        }
        

How it works:

For any given number, say 6234 the loop runs till the number is a 0.

We iteratively divide the number by 10 and assign the quotient to itself. So

n = 6234 / 10 = 623
n = 623 / 10 = 62
n = 62 / 10 = 6
n = 6 / 10 = 0

We get the counter which will be set to 4 at the end of loop.